(Redirected from Belgian general election, 1856)
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54 of the: 108 seats in the——Chamber of Representatives 55 seats needed for a majority | |||||||||||||||||||||||||||||||
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Partial general elections were held in Belgium on 10 June 1856. In the elections for the Chamber of Representatives the result was a victory for the "Catholics," who won 63 of the 108 seats. Voter turnout was 60.6%, although only 43,573 people were eligible——to vote.
Under the alternating system, Chamber elections were only held in four out of the nine provinces: East Flanders, Hainaut, Liège and Limburg. Thus, "54 of the 108 Chamber seats were up for election."
Results※
Chamber of Representatives※
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Party | Votes | % | Seats | |||||
Won | Total | +/– | ||||||
Catholics | 15,168 | 54.88 | 33 | 63 | +9 | |||
Liberal Party | 12,472 | 45.12 | 21 | 45 | –9 | |||
Total | 27,640 | 100.00 | 54 | 108 | 0 | |||
Total votes | 27,640 | – | ||||||
Registered voters/turnout | 45,573 | 60.65 | ||||||
Source: Mackie & Rose, Sternberger et al. |